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A simple harmonic oscillator's velocity is given by vy(t) = (0.86 m/s)sin(11t − 5.55). Find the oscillator's position, velocity, and acceleration at each of the following times. (Include the sign of the value in your answer) a) t = 0s

b) t = 0.5s c) t = 2s

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1 answer

  1. dv/dt=acceleration
    INt dv = -cos(11t-5.55) (.86/11)= position

    plug in t, and you have it.

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    bobpursley

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