A simple harmonic oscillator's velocity is given by vy(t) = (0.86 m/s)sin(11t − 5.55). Find the oscillator's position, velocity, and acceleration at each of the following times. (Include the sign of the value in your answer) a) t = 0s
b) t = 0.5s c) t = 2s
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dv/dt=acceleration
INt dv = cos(11t5.55) (.86/11)= position
plug in t, and you have it. 👍
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👤bobpursley
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