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A 1.50 kg sample of a metal sample absorbs 43.5 kJ of heat, resulting in a

Temperature rise of 65.0 °C. What is the specific heat capacity of the metal?

M=1.50kG
Q=43.5kJ
dT=65C

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2 answers
  1. q= mass x specific heat x delta T.
    I don't know what units you want sp.h. in but I would convert kJ to J and kg to g. That way sp.h. comes out in J/g*C and you can convert to whatever you want.

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  2. Thanks bob that was my problem

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