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If a gas effuses 1.618 times faster than Kr (molar mass = 83.8 g/mol) what is the molar

mass of the gas?

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2 answers
  1. 1.618/1=sqrt( 83.8/molmassX)
    square both sides.
    molmassX=83.8/1.618^2
    x=32

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    bobpursley
  2. Thank you

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