Nitrogen (N2) and hydrogen (H2) react to form ammonia (NH3). Consider a mixture of six nitrogen molecules and six hydrogen molecules in a closed container. Assuming the reaction goes to completion, what will the final product mixture be?
number of NH3 molecules
number of N2 molecules
number of H2 molecules
Which of the following equations best represents this reaction?42 N2 + 6 H2 4 NH3
6 N2 + 6 H2 4 NH3 + 4 N2
N + 3 H2 NH3
N2 + 3 H2 2 NH3
N2 + H2 NH3
i know the answers but i have no idea how to do it whih doesnt help. Can someone please explain how to do it?
#1. Write the equation and balance it.
N2 + 3H2 ==> 2NH3
initial concn.
N2 = 6 N2 molecules
H2 = 6 H2 molecules
NH3 = 0 molecules.
If it goes to completion, one of these must be the limiting reagent. How much NH3 would 6 molecules N2 produce? That will be
6 molecules N2 x (2 moles NH3/1 mole N2) = 12 molecules NH3.
How much NH3 would 6 molecules H2 produce?
6 molecules H2 x (2 moles NH3/3 moles H2) = 4 molecules NH3.
The smaller number is 4; therefore, H2 is the limiting reagent and 4 molecules NH3 will be produced. How much N2 will that use.
6 molecules H2 x (1 mole N2/3 moles H2) = 2 molecules N2.
Final mixture:
NH3 = 4 molecules
H2 = 6 molecules to start; we used 6 so we end up with 0 molecules H2.
N2 = We start with 6 molecules, we use 2 molecules N2 so we are left with 6-2=4.
Check my work.
If you wrote the balanced chemical equation you know the answer.
okay that makes perfect sense thanks :)
СЧЕа
Well, if you know the answers already, then what's the point in explaining it? Just kidding! I'm here to help, so let's get started with the explanation.
First, let's identify the number of nitrogen molecules (N2) and hydrogen molecules (H2) we have in the mixture. We are given that there are six nitrogen molecules and six hydrogen molecules.
Now, we need to understand the stoichiometry of the reaction. The balanced equation should tell us the ratio of reactants and products. In this case, the equation is:
N2 + 3 H2 -> 2 NH3
From the equation, we can see that one molecule of nitrogen (N2) reacts with three molecules of hydrogen (H2) to produce two molecules of ammonia (NH3).
So, let's calculate the final product mixture:
Nitrogen molecules (N2): We start with six molecules of nitrogen (N2), and since each molecule of nitrogen forms two molecules of ammonia (NH3), we will have 6 x 2 = 12 molecules of ammonia (NH3) as the final product.
Hydrogen molecules (H2): We start with six molecules of hydrogen (H2), and since each molecule of nitrogen reacts with three molecules of hydrogen, we will need 6 x 3 = 18 molecules of hydrogen (H2) to react completely. However, we only have six molecules of hydrogen, so it will be the limiting reactant. This means that all six molecules of hydrogen will be used up in the reaction, and we won't have any leftover hydrogen molecules.
Therefore, the final product mixture will consist of:
12 molecules of ammonia (NH3)
Zero molecules of nitrogen (N2)
Zero molecules of hydrogen (H2)
Regarding the equation that represents this reaction, it would be N2 + 3 H2 -> 2 NH3.
I hope this explanation has cleared things up for you! If you have any further questions, feel free to ask!
To determine the final product mixture, we need to balance the given chemical reaction equation first. Balancing the equation involves making sure that the same number of atoms of each element is present on both sides of the equation.
Let's analyze the given options one by one:
1. 42 N2 + 6 H2 → 4 NH3:
This equation is not balanced since the number of hydrogen atoms is not equal on both sides.
2. 6 N2 + 6 H2 → 4 NH3 + 4 N2:
In this equation, the number of nitrogen atoms is not balanced, as there are 6 nitrogen atoms on the left side and 8 nitrogen atoms on the right side.
3. N + 3 H2 → NH3:
This equation is incorrect because the reactant on the left side is an individual nitrogen atom (N), while it should be a nitrogen molecule (N2).
4. N2 + 3 H2 → 2 NH3:
This equation is balanced correctly, with two nitrogen atoms and six hydrogen atoms on both sides.
5. N2 + H2 → NH3:
Similar to option 3, this equation is incorrect because the reactant on the left side is a single hydrogen atom (H), while it should be a hydrogen molecule (H2).
Therefore, option 4, N2 + 3 H2 → 2 NH3, best represents the given reaction.
Now that we have the balanced equation, we can determine the number of molecules present in the final product mixture by comparing the coefficients of the balanced equation.
From the balanced equation, we see that 1 molecule of N2 reacts with 3 molecules of H2 to form 2 molecules of NH3.
In the given mixture, there are 6 molecules of N2 and 6 molecules of H2. Since the reaction goes to completion, all N2 and H2 will react.
Using the stoichiometry of the balanced equation, we can calculate the number of NH3 molecules formed:
6 N2 + 18 H2 → 12 NH3
Therefore, the final product mixture will contain 12 molecules of NH3, 0 molecules of N2, and 0 molecules of H2.