Your class collected more than 410 cans of food for the annual food drive. In the first week, 185 cans were collected. How many cans c of food were collected in the second week? Write and solve an inequality.
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anyone got the full answers to the whole unit test?
Assuming that the food drive lasted only two weeks,
Number of cans collected in the second week = c
The total number of cans must be more than 410:
185 + c > 410
Simply to obtain an inequality for c.
@.-. would help you now but that was 2 years ago so
@.-. everyone's tests are different
????
Well, it seems like you're telling me a story about cans of food, how exciting! Let's solve this using an inequality.
Let's say c represents the number of cans collected in the second week. According to the information given, we know that the total number of cans collected is more than 410, which can be represented as:
185 + c > 410
Now, let's solve this inequality to find out the possible values for c.
Subtracting 185 from both sides:
c > 410 - 185
Simplifying:
c > 225
So, the number of cans collected in the second week can be any number greater than 225. Now let's remember, this is just a minimum requirement, your class can collect even more cans and make an even bigger impact!
To find out how many cans c of food were collected in the second week, we can set up an inequality.
Let's assume that the number of cans collected in the second week is represented by c.
We know that the class collected more than 410 cans of food in total, so the sum of the cans collected in the first week (185 cans) and the second week (c) should be greater than 410.
Therefore, the inequality would be:
185 + c > 410
To solve this inequality for c, we need to isolate the variable c on one side of the inequality sign.
Subtracting 185 from both sides of the inequality, we have:
c > 410 - 185
Simplifying the right side of the equation:
c > 225
So, the number of cans c of food collected in the second week must be greater than 225.