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A vinegar contains acetic acid, CH3COOH. Titration of 5.000g of vinegar with 0.100, NaOH requires 33.0 ml to reach equivalent point. What is the weight percentage of CH3COOH in vinegar?

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4 answers

  1. It's been said in Vinegar. So it suppose to be 0.198/5 * 100

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  2. CH3COOH + NaOH ==> CH3COONa + H2O

    mols NaOH =- M x L = 0.1 x 0.033 = 0.033
    mols CH3COOH = mols NaOH from above.
    g CH3COOH = mols CH3COOH x molar mass CH3COOH.
    % CH3COOH = (g CH3COOH/mass sample)*100 = ?

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  3. 0.033/0.198*100=16.67%

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  4. 16.67

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