Find the distance using the appropriate arch length.
A television tower 520m high subtends an angle of 2deg30'. How far away is the tower?
some people that helped me alot were Reiny, Damon, bobpursley, and drwls..so i just wanna say thnks to you guys...are u guys math expersts or sometig
:)..can you also please explain how to do it
520m/(distance) = tan 2.5 degrees = 0.0437
Solve for the distance.
i don't get it ,,,why are there three different sides in the equation??
He just said that tan 2.5 deg was .0437
i get an answer that's not one of my choices..
A. 23m
B. 2300m
C. 11925m
D. 20850m
C. is the closest answer. The exact answer depends upon whether you are talking about the distance to the top or the base of the tower. If the top, use sin 2.5 instead of tan 2.5. That will get you an answer of 11921 m.
All of their choices have too many significant figures, considering that there are only three significant figures in 2.50 degrees