Use scalar multiplication to find the coordinates of the vertices of each figure for a dilation centered at the

origin with the given scale factor.

Parallelogram JKLM with J(−4, 3), K(−4, 7), L(2, 7), M(2, 3); r = 5

Thank you!

just multiply all the numbers by 5.

!!

So you mean (-4,3) becomes (-20,15)?

and so on?

bingo

To find the coordinates of the vertices of the dilated parallelogram, you will need to use scalar multiplication. Scalar multiplication involves multiplying each coordinate of a point by a scalar, which is the scale factor.

Given the parallelogram JKLM with the following coordinates:
J(-4, 3), K(-4, 7), L(2, 7), M(2, 3)

And the scale factor r = 5

To find the new coordinates, you will multiply each coordinate by the scale factor:

For point J(-4, 3):
New x-coordinate: -4 * 5 = -20
New y-coordinate: 3 * 5 = 15

So the new coordinate for J is (-20, 15).

For point K(-4, 7):
New x-coordinate: -4 * 5 = -20
New y-coordinate: 7 * 5 = 35

So the new coordinate for K is (-20, 35).

For point L(2, 7):
New x-coordinate: 2 * 5 = 10
New y-coordinate: 7 * 5 = 35

So the new coordinate for L is (10, 35).

For point M(2, 3):
New x-coordinate: 2 * 5 = 10
New y-coordinate: 3 * 5 = 15

So the new coordinate for M is (10, 15).

Therefore, the new coordinates for the vertices of the dilated parallelogram with a scale factor of 5 are:
J'(-20, 15), K'(-20, 35), L'(10, 35), M'(10, 15).