write an equation in slope intercept form for the line that has a slope of 2/3 and y intercept of (0,-5)

you have a point and a slope. Recall that the line through (h,k) with slope m is

y-k = m(x-h)

so, plug in your numbers.

equation=change in y/change in x=slope. so y--5/x-0=2/3. cross multiply so the equation will be 3y 15=2x 0

To write an equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we can substitute the given values:

Slope (m) = 2/3
Y-intercept (b) = -5

Therefore, the equation is:

y = (2/3)x - 5

To write the equation of a line in slope-intercept form (y = mx + b), you need to know the slope (m) and the y-intercept (b).

Given that the slope is 2/3 and the y-intercept is (0, -5), we can substitute these values into the slope-intercept equation.

The slope-intercept form equation is y = mx + b, where:
- y represents the y-coordinate of a point on the line.
- m represents the slope of the line.
- x represents the x-coordinate of a point on the line.
- b represents the y-intercept of the line.

Since the given y-intercept is at (0, -5), we know that when x = 0, y = -5.

Substituting the values into the equation, we get:
y = (2/3)x - 5

Therefore, the equation of the line with a slope of 2/3 and a y-intercept of (0, -5) is y = (2/3)x - 5.