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A scuba diver’s tank contains 0.29 kg of O2 compressed into a volume of 2.3L.

A)calculate the gas pressure inside the tank at 9 Celsius.
B) what volume would this oxygen occupy at 26 Celsius and 0.95atm?

Answer is a)91atm
B) 2.3 x 10^2 L
Trying to find out how they got these. Please do it step by step with me.

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4 answers
  1. Use PV = nRT for both.
    Post your work of I can help you through it if you have problems.

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  2. Okay.
    PV = nRT
    ATM * 2.3L = n (0.08205)(282k)

    How do I do “n”?

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  3. Okay.
    PV = nRT
    ATM * 2.3L = n (0.08205)(282k)

    How do I do “n”?

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  4. Please don't confuse us with different screen names. n = grams/molar mass. R = 0.082057 L*atm/mol*K and I usually round that to 0.08206.

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