1) Maria is 6 times as old as Tina. In twenty years, Maria will be only twice as old as Tina. How old is Maria now?
Please explain how you got your answer. Thanks!
2)
Rating. Relative speed of flow
10W. Half as fast as 5W
15W. Half as fast as 10W
20W. Half as fast as 15W
2) According to the table above, car engine oil with a rating of 5W flows how many times as fast as car engine oil with a rating of 20W?
3) Ti and G both collect stamps. The number of stamps in Ti collection is 3 less than 5 times the number of G's collection
A How many number of stamps are in Tina's collection?
***T=5G-3***
B The number of stamps in G's collection
***J***
Answer choices-
D) Answer A is bigger
L) answer B is bigger
S) answers are the same
T) Relationshio can not be determined ***
1)
m = 6t
m+20 = 2(t+20)
6t+20 = 2t+40
t=5
So, Mary is 30
in 20 years she will be 50, which is 2*25
2)5W = 2*10W = 4*15W = 8*20W
3) makes no sense, either the question of the answers
1) To solve this problem, let's set up equations to represent the given information. Let's say Tina's age is represented by T, and Maria's age is represented by M.
According to the problem, Maria is 6 times as old as Tina, so we can write the equation: M = 6T.
In twenty years, Maria will be twice as old as Tina, so we can write the equation: M + 20 = 2(T + 20).
To solve for Maria's age now, we can substitute the value of M from the first equation into the second equation:
6T + 20 = 2(T + 20).
Simplifying the equation, we get:
6T + 20 = 2T + 40.
Combining like terms, we get:
4T = 20.
Dividing both sides by 4, we get:
T = 5.
So Tina is currently 5 years old. To find Maria's age, we can substitute this value into the first equation:
M = 6(5) = 30.
Therefore, Maria is currently 30 years old.
2) According to the table provided, a car engine oil with a rating of 5W flows half as fast as car engine oil with a rating of 10W. Similarly, a car engine oil with a rating of 10W flows half as fast as 15W, and 15W flows half as fast as 20W.
So, we can conclude that a car engine oil with a rating of 5W flows one-fourth (half of half) as fast as car engine oil with a rating of 20W.
3) According to the information given, the number of stamps in Tina's collection is 3 less than 5 times the number of G's collection, represented as T = 5G - 3.
Since we don't have any specific values or relationship mentioned between Tina's and G's collections, the exact number of stamps in each collection cannot be determined. Thus, the answer is T) Relationship cannot be determined.
1) To solve this problem, we can start by setting up an equation based on the information given. Let's use M to represent Maria's age and T to represent Tina's age.
We are told that Maria is 6 times as old as Tina, which can be written as M = 6T.
In twenty years, Maria will be only twice as old as Tina. This can be written as M + 20 = 2(T + 20).
Now we have two equations: M = 6T and M + 20 = 2(T + 20).
We can solve this system of equations by substituting the value of M from the first equation into the second equation.
Substituting M = 6T into M + 20 = 2(T + 20), we get 6T + 20 = 2(T + 20).
Expanding the equation gives us 6T + 20 = 2T + 40.
Simplifying further, we have 6T - 2T = 40 - 20, which gives us 4T = 20.
Dividing both sides by 4, we find T = 5.
Now that we know Tina's age is 5, we can substitute this value back into the first equation to find Maria's age.
M = 6T = 6 * 5 = 30.
Therefore, Maria is currently 30 years old.
2) According to the table, we can see that each rating is half as fast as the one before it.
Starting with the rating of 5W, we can determine the number of times it flows faster than the 20W rating by using the following reasoning:
5W is twice as fast as 10W, so 10W is half as fast as 5W.
10W is twice as fast as 15W, so 15W is half as fast as 10W.
15W is twice as fast as 20W, so 20W is half as fast as 15W.
Therefore, car engine oil with a rating of 5W flows twice as fast as car engine oil with a rating of 20W.
3) The equation given is T = 5G - 3.
To find the number of stamps in Tina's collection (T), we substitute the value of G into this equation.
Without G's value given, we cannot determine the exact number of stamps in Tina's collection (T). So the equation T = 5G - 3 gives us the relationship between the two quantities rather than the specific values.
Therefore, the answer to part A is: Relationship cannot be determined (option T).
For part B, the number of stamps in G's collection (J) is not given, so we cannot determine its value. Therefore, the answer to part B is: The number of stamps in G's collection is not determined.