In a two-digit number the tens digit is two less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 154. Find the original number.
(n-2) n is (n-2)10 + n = 11 n-20
n (n-2) is 10 n + n-2 = 11 n - 2
sum = 22 n - 22 = 154
so
22 n = 176
n = 8
so
68
(n-2) n is (n-2)10 + n = 11 n-20
n (n-2) is 10 n + n-2 = 11 n - 2
The sum = 22 n - 22 = 154, so we can understand that:
22 n = 176
After solving the equation;
n = 8
So, the answer is 68.
I hope this helped!
68 trust me
68
73
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