A body accelerates from rest at 0.2m/s for one-fifth of a minute.Calculate the distance covered by the body.
I think you might mean 0.2 m/s^2
d = (1/2) a t^2
a = 0.2 m/s^2
t = 60/5 = 12 seconds
d = (1/2)(.2)(144) = 14.4 meters
d=1/2 a t^2=1/2 *.2 m/s^2 *12^2 s^2
can't you solve the question clearly.
Damon not one-fifth but 20seconds so solve again
Use this formula (s=ut+1/2at2)
That will give us 14.4m