Leila will rent a car for the weekend. She can choose one of two plans. The first plan has no initial fee but costs $0.70 per mile driven. The second plan has an initial fee of $65 and costs an additional $0.50 per mile driven. How many miles would Leila need to drive for the two plans to cost the same?

65 + .5 x = .7 x

.2 x = 65

x = 65/.2

Let's assume that Leila will drive "x" miles.

For the first plan, the cost is $0.70 per mile driven, so the total cost would be 0.70 * x.

For the second plan, the cost is $0.50 per mile driven plus an initial fee of $65, so the total cost would be 0.50 * x + 65.

We need to find the value of "x" when the two plans cost the same, so we can set up the equation:

0.70 * x = 0.50 * x + 65

We can simplify the equation:

0.20 * x = 65

Now, divide both sides of the equation by 0.20 to solve for "x":

x = 65 / 0.20

x = 325

Therefore, Leila would need to drive 325 miles for the two plans to cost the same.

To find out how many miles Leila would need to drive for the two plans to cost the same, we can set up an equation.

Let's denote the number of miles driven as "m".

For the first plan, the cost is $0.70 per mile driven and there is no initial fee. Therefore, the cost can be calculated as 0.70m.

For the second plan, there is an initial fee of $65 and an additional cost of $0.50 per mile driven. So the cost can be calculated as 65 + 0.50m.

We want to find the point at which the cost for both plans is the same, so we can set up the following equation:

0.70m = 65 + 0.50m

To solve for m, we can subtract 0.50m from both sides of the equation:

0.70m - 0.50m = 65

0.20m = 65

Now, divide both sides of the equation by 0.20 to solve for m:

m = 65 / 0.20

m = 325

Therefore, Leila would need to drive 325 miles for the two plans to cost the same.

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