Separate the following balanced chemical equation into its total ionic equation.
AgNO3(aq)+NaCl(aq) --> NaNO3(aq)+AgCl(s)
(List the ions in order of the above equation.)
Write the net ionic equation for the reaction above. (Make sure the cation is first and anion is second.)
To save time I will omit the aq part but you can add that to each cation and anion yourself. I have added (s) to the AgCl to show it is solid.
Ag^+ NO3^- + Na^+ + Cl^- ==> Na^+ + NO3^- + AgCl(s)
Cancel the ions on each side that are common to both sides to end up with the net ionic equation.
Ag^+(aq) + Cl^-(aq) ==> AgCl(s)
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Oh, chemistry! Always trying to keep things balanced. Well, let's break down this equation and have a little fun with it.
Balanced chemical equation:
AgNO3(aq) + NaCl(aq) --> NaNO3(aq) + AgCl(s)
To find the total ionic equation, we need to break down the compounds into their respective ions:
Total ionic equation:
Ag+(aq) + NO3-(aq) + Na+(aq) + Cl-(aq) --> Na+(aq) + NO3-(aq) + AgCl(s)
Now, for the net ionic equation, we have to eliminate the spectator ions (the ones that are present on both sides of the equation and don't actively participate in the reaction):
Net ionic equation:
Ag+(aq) + Cl-(aq) --> AgCl(s)
There you have it! A neat little equation where the Ag+ cation and Cl- anion come together to form a solid AgCl. Chemistry sure knows how to bring people (or should I say ions) together!
To separate a balanced chemical equation into its total ionic equation, you need to first identify the ions present in each compound.
In the given balanced equation: AgNO3(aq) + NaCl(aq) -> NaNO3(aq) + AgCl(s)
Here are the ions present in each compound:
- AgNO3: Ag+ and NO3-
- NaCl: Na+ and Cl-
- NaNO3: Na+ and NO3-
- AgCl: Ag+ and Cl-
Now, let's write the total ionic equation by representing all soluble ionic compounds as their dissociated ions:
Ag+(aq) + NO3-(aq) + Na+(aq) + Cl-(aq) → Na+(aq) + NO3-(aq) + AgCl(s)
In the total ionic equation, the ions common on both sides are called spectator ions. In this case, Na+ and NO3- are the spectator ions because they appear unchanged on both sides of the equation.
Thus, the net ionic equation is obtained by removing the spectator ions:
Ag+(aq) + Cl-(aq) → AgCl(s)
In the net ionic equation, only the ions involved in the actual chemical change are shown.