Tickets to a sporting event cost $6 for children and $8 for adults. The total revenue from the tickets sold was $2340. There were 320 total tickets sold.

How many children’s tickets were sold?

c + a = 320

6c + 8a = 2340

8c + 8a = 8(320)

2c = 8(320) - 2340

110 children's tickets were sold and 210 adult tickets were sold. Using the first 2 equations set up by Scott & ignoring the last 2 steps, I used substitution to solve for c "the number of children's tickets sold.

6c+8(320-c)=320

6c+2560-8c=320

-2c+2560=320

-2c=-220

c=110

Let's assume that the number of children's tickets sold is denoted by C, and the number of adult tickets sold is denoted by A.

According to the given information, the cost of each child's ticket is $6 and the cost of each adult ticket is $8.

Now, we can set up two equations to represent the given information:

1. C + A = 320 (because the total number of tickets sold is 320)
2. 6C + 8A = 2340 (because the total revenue from the ticket sales is $2340)

To solve this system of equations, we can use substitution or elimination method. Let's use the substitution method.

From equation 1, we have A = 320 - C.

Substituting this into equation 2, we get:

6C + 8(320 - C) = 2340
6C + 2560 - 8C = 2340
-2C = 2340 - 2560
-2C = -220
C = -220 / -2
C = 110

Therefore, the number of children's tickets sold is 110.

To solve this problem, we can set up a system of equations based on the given information.

Let's assume that the number of children's tickets sold is C, and the number of adult tickets sold is A.

According to the problem, the cost of a children's ticket is $6, so the total revenue from children's tickets would be 6C. Similarly, the total revenue from adult tickets, given that the cost of an adult ticket is $8, would be 8A.

We also know that the total revenue from all the tickets sold is $2340. So, we can write the equation:

6C + 8A = 2340

Additionally, we know that the total number of tickets sold is 320, so we can write another equation:

C + A = 320

We now have a system of two equations with two variables. We can solve this system of equations to find the values of C and A.

One way to solve this system is by substitution. We can solve the second equation for C, which will give us an expression for C in terms of A. So, let's solve the second equation for C:

C = 320 - A

Now, we can substitute this expression for C into the first equation:

6(320 - A) + 8A = 2340

Let's simplify and solve for A:

1920 - 6A + 8A = 2340

2A = 420

A = 210

Now that we have the value of A, we can substitute it back into the second equation to find the value of C:

C + 210 = 320

C = 320 - 210

C = 110

Therefore, the number of children's tickets sold is 110.