A man was 27 years older than his son ten years ago.His wife is 4 years younger than he is.if their total age is 116 years now ,how old is the son?
Let's solve this step-by-step:
1. Let's assume the son's age as "x" now.
2. Ten years ago, the man's age was (x + 27) - 10 (as he was 27 years older than his son 10 years ago).
3. The wife's age is 4 years younger than the man's age, so her age ten years ago would be ((x + 27) - 10) - 4.
4. Now, let's calculate the present age of the man: (x + 27) + 10.
5. Adding the present ages of the man, his wife, and the son gives the total age of 116 years: (x + 27) + 10 + (((x + 27) - 10) - 4) + x = 116.
6. Simplifying the equation: x + 27 + 10 + x - 10 - 4 + x = 116.
7. Combining like terms: 3x + 23 = 116.
8. Subtracting 23 from both sides of the equation: 3x = 93.
9. Dividing both sides by 3: x = 31.
Therefore, the son is 31 years old.
To solve this problem, we need to set up equations based on the given information. Let's represent the current age of the son as "x" years.
1. We are told that ten years ago, the man was 27 years older than his son. So, ten years ago, the man's age would have been (x - 10) + 27.
2. We are also told that the man's wife is 4 years younger than he is. So, the current age of the wife would be [(x - 10) + 27] - 4.
3. Lastly, the total age of the man, his wife, and their son is given as 116 years. So, we can write an equation: (x - 10) + [(x - 10) + 27] + [(x - 10) + 27 - 4] = 116.
Now, let's solve this equation to find the value of x, which represents the son's current age.
(x - 10) + [(x - 10) + 27] + [(x - 10) + 27 - 4] = 116
Simplify the equation:
x - 10 + x - 10 + 27 + x - 10 + 27 - 4 = 116
3x - 39 = 116
Now, let's solve for x:
3x = 116 + 39
3x = 155
x = 155 / 3
x ≈ 51.67
Therefore, the son's current age is approximately 51.67 years.
I am not getting the answer
M - 27 = S
M - 4 = W
M + W + S = 116
Substitute M-27 and M-4 for S and W respectively in the third equation and solve for M. Insert that value into the first equation to solve for S.