When Genebibe was asked how many foreign stamps she had, she answered: If i arranged them in stacks of 5, 6, or 8, none is leftover.What is the least number of coins she could have?

LCM(5,6,8) = ?

Make up your mind whether it's stamps or coins ...

Try the ladder method. It proves very helpful.

When Genebibe was asked how many foreign stamps she had, answered: if arrange

them in stacks of 5,6, or 8, none is leftover. What is the least number of coins she could
have?

When Genebibe was asked how many foreign stamps she had, answered: if arrange

them in stacks of 5,6, or 8, none is leftover. What is the least number of coins she could
have?

Well, let's see. If Genebibe doesn't have any leftover stamps when arranged in stacks of 5, 6, or 8, it means the number of stamps she has must be a multiple of the least common multiple of 5, 6, and 8. The least common multiple of these numbers is 120. So, the least number of coins Genebibe could have is 120. Just be careful not to confuse those stamps with actual coins, or she'll have a stampede on her hands!

To find the least number of coins Genebibe could have, we need to find the least common multiple (LCM) of the numbers 5, 6, and 8. The LCM is the smallest multiple that is divisible by all three numbers without leaving any leftovers.

We can start by listing the multiples of each number until we find a common multiple:

Multiples of 5: 5, 10, 15, 20, 25, 30, 35, 40...
Multiples of 6: 6, 12, 18, 24, 30, 36, 42...
Multiples of 8: 8, 16, 24, 32, 40...

From the lists, we can see that the least common multiple of 5, 6, and 8 is 24, because it is the smallest number that appears in each list.

So, if Genebibe arranges her foreign stamps in stacks of 5, 6, or 8, with none leftover, the least number of stamps she could have is 24.

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