Write a net ionic equation for the reaction that occurs when excess hydrobromic acid (aq) and sodium sulfide are combined.
Write a net ionic equation for the reaction that occurs when aqueous solutions of barium hydroxide and hypochlorous acid are combined.
To write the net ionic equation for the reaction between hydrobromic acid and sodium sulfide, we first need to write the balanced chemical equation.
The chemical equation for the reaction is:
2 HBr (aq) + Na2S (aq) → 2 NaBr (aq) + H2S (g)
Now let's break down the equation into its respective ions and write the full ionic equation:
2 H+ (aq) + 2 Br- (aq) + 2 Na+ (aq) + S2- (aq) → 2 Na+ (aq) + 2 Br- (aq) + H2S (g)
Finally, we can cancel out the spectator ions, which are the ions that are present on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are the sodium cations (Na+):
2 H+ (aq) + S2- (aq) → H2S (g)
This is the net ionic equation for the reaction between hydrobromic acid and sodium sulfide.
To write the net ionic equation for the reaction between hydrobromic acid (HBr) and sodium sulfide (Na2S), we first need to identify the balanced molecular equation.
The chemical equation for the reaction is:
2 HBr(aq) + Na2S(aq) → 2 NaBr(aq) + H2S(g)
In this equation, hydrobromic acid (HBr) reacts with sodium sulfide (Na2S) to form sodium bromide (NaBr) and hydrogen sulfide (H2S).
Next, we need to separate the equation into its ionic components. In aqueous solutions, hydrobromic acid and sodium sulfide will dissociate into their respective ions:
2 H+(aq) + 2 Br-(aq) + 2 Na+(aq) + S2-(aq) → 2 Na+(aq) + 2 Br-(aq) + H2S(g)
Now, we can see that the sodium ions (Na+) and bromide ions (Br-) are present on both sides of the equation, which means they are spectator ions. Spectator ions do not participate in the reaction, so we can eliminate them from the equation.
The resulting net ionic equation would be:
S2-(aq) + 2 H+(aq) → H2S(g)
This net ionic equation represents the essential species and the actual reaction taking place in the solution. It shows that sulfide ions (S2-) react with hydrogen ions (H+) to form hydrogen sulfide gas (H2S).
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