Login or Sign Up
Ask a New Question

how do you solve for y in the expression: x^3=y(y+3)?

x^3=y^2 + 3y
y^2+3y- x^3=0

Using the quadratic formula..

y= (-3+-sqrt(9+4x^3) )/2

1 answer

  1. 5x

Answer this Question

Still need help?

You can ask a new question or browse more Math questions.