A force of 40N is applied at the end of a wire 4m long and it produces an extension of 0.24mm.if the diameter of the wire is 2.0mm.calculate the stress and strain of the wire

force of 40N is applied at the end of a wire 4m long and it produces an extension of 0.24mm.if the diameter of the wire is 2.0mm.calculate the stress and strain of the wire

notine

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I haven't seen d answer finished

To calculate the stress and strain of the wire, we need to use the formulas:

Stress = Force / Area
Strain = Extension / Original Length

1. First, let's calculate the area of the wire using the formula:

Area = π * (diameter/2)^2

Plugging in the values:
Area = π * (2.0mm / 2)^2
Area = π * (1.0mm)^2
Area = π * 1.0mm^2
Area = π mm^2

2. Now, let's convert the diameter and area to meters for consistency in the units:

Diameter = 2.0mm = 2 * 10^-3 m
Area = π * (1.0mm)^2 = π * (1 * 10^-3 m)^2 = π * 1 * 10^-6 m^2

3. Now we can calculate the stress using the formula:

Stress = Force / Area

Plugging in the values:
Stress = 40N / (π * 1 * 10^-6 m^2)
Stress = 40N / π * 10^-6 m^2
Stress = 4 * 10^7 / π N/m^2

4. Next, let's calculate the strain using the given values:

Strain = Extension / Original Length

Plugging in the values:
Strain = 0.24mm / 4m
Strain = 0.24 * 10^-3 m / 4m
Strain = 6 * 10^-5

Therefore, the stress of the wire is approximately 4 * 10^7 / π N/m^2 and the strain is approximately 6 * 10^-5.