I music store gives every 20th customer a five dollar gift card. Every 50th customer gets a $10 gift card. Which customer will be the first to receive both types of gift cards?
Technically, since the 20th and 50th gets gift cards,
it would be the least common multiple or LCM of 20 and 50.
20: 20, 40, 60, 80, 100, 120 , 140
50: 50, 100, 150, 200
The LCM would be 100
20*5 = 50*2 = 100
Nice job on the math problems
A grocery store gives away a $10 gift card to every 25th customer and a $20 gift card to every 60th customer.
honestly just slayed like everyday 💅
Well, I guess the first customer who manages to bring a monkey that can play the drums while juggling pineapples will definitely be the lucky winner of both gift cards! It might take a while though, so make sure to bring your circus skills and a lot of patience. Good luck!
To solve this problem, we need to determine the common multiples of 20 and 50.
First, let's find the multiples of 20:
20, 40, 60, 80, 100, 120, 140, ...
Next, let's find the multiples of 50:
50, 100, 150, 200, 250, 300, ...
To find the common multiples of 20 and 50, we need to look for numbers that appear in both lists. From the lists above, we can see that the first common multiple is 100.
Therefore, the first customer to receive both types of gift cards will be the 100th customer.