The rectangle below has an area of 30k^3+6k^2
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2
What is the width and length of the rectangle?
Width:6k^2
Length:
I couldn't find the length I need to be explained of how to find it because I feel like I know how to do it but its playing with me.
30k^3+6k^2 = (6k^2)(5k+1)
(6k2)(5tk1)
To find the length of the rectangle, we can divide the total area by the width. In this case, the total area of the rectangle is given as 30k^3 + 6k^2, and the width is given as 6k^2.
So, we divide the total area by the width:
Length = (30k^3 + 6k^2) / (6k^2)
To simplify this expression, we can factor out the greatest common monomial factor from the numerator (30k^3) and denominator (6k^2), which is 6k^2:
Length = (6k^2 * 5k + 6k^2 * 1) / (6k^2)
Simplifying further:
Length = (30k^3 + 6k^2) / (6k^2)
= (6k^2 * 5k + 6k^2 * 1) / (6k^2)
= (6k^2) * (5k + 1) / (6k^2)
= 5k + 1
Therefore, the length of the rectangle is 5k + 1.
The rectangle below has an area of 30k^3+6k^230k
3
+6k
2
square meters.
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^330k
3
and 6k^26k
2
.
What is the length and width of the rectangle?
\text{Width} = Width=
meters
\text{Length} = Length=
meters