The rectangle below has an area of 30k^3+6k^2

The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2

What is the width and length of the rectangle?

Width:6k^2
Length:

I couldn't find the length I need to be explained of how to find it because I feel like I know how to do it but its playing with me.

3 answers

  1. 30k^3+6k^2 = (6k^2)(5k+1)

  2. The rectangle below has an area of 30k^3+6k^230k
    3
    +6k
    2
    square meters.
    The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^330k
    3
    and 6k^26k
    2
    .
    What is the length and width of the rectangle?



    \text{Width} = Width=
    meters
    \text{Length} = Length=
    meters

  3. (6k2)(5tk1)

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