a graduated cylinder contains 135 ml of water. a 11.0 g piece of iron (d=7.86g/ml ) and a 24.0 g piece of lead (d=11.3g/ml) are added. what is the new water level in the cylinder?
Mass = volume x density
volume Pb = mass/density
volume Fe = mass/density
Total volume Fe&Pb=volume Pb + volume Fe
Total volume in cylinder = volume water + volume of Pb & Fe.
I'm lost in which number goes where
C'mon. It makes no sense to me that you don't know which number goes where.
volume Pb = mass/density.
mass Pb = 24.0 g. Right? It says that in the problem.
density = 11.3 g/mL. Right? It says that in the problem.
I think you want someone to work the problem for you.
To find the new water level in the graduated cylinder after adding the pieces of iron and lead, we need to calculate the total volume occupied by the iron and lead and subtract it from the initial volume of water in the cylinder.
Step 1: Calculate the volume occupied by the iron:
We are given the density of iron (d = 7.86 g/ml) and the mass of the iron piece (m = 11.0 g). We can use the formula:
Volume (V) = Mass (m) / Density (d)
V(iron) = 11.0 g / 7.86 g/ml
Step 2: Calculate the volume occupied by the lead:
We are given the density of lead (d = 11.3 g/ml) and the mass of the lead piece (m = 24.0 g). We can use the same formula:
V(lead) = 24.0 g / 11.3 g/ml
Step 3: Calculate the total volume occupied by the iron and lead:
Total Volume = V(iron) + V(lead)
Step 4: Calculate the new water level:
New Water Level = Initial Water Level - Total Volume
Now, let's perform the calculations:
Step 1:
V(iron) = 11.0 g / 7.86 g/ml ≈ 1.40 ml
Step 2:
V(lead) = 24.0 g / 11.3 g/ml ≈ 2.12 ml
Step 3:
Total Volume = 1.40 ml + 2.12 ml ≈ 3.52 ml
Step 4:
New Water Level = 135 ml - 3.52 ml ≈ 131.48 ml
Therefore, the new water level in the graduated cylinder after adding the pieces of iron and lead is approximately 131.48 ml.