1. A glass flask whose volume is exactly 1000cm^3 at 0 degrees Celsius is completely filled with mercury at this temperature. When the flask and mercury are heated to 100 degrees Celsius, 15.2cm^3 of mercury overflow. If the coefficient of volume expansion of mercury is 18 x 10^-5 per Celsius degree, compute the coefficient volume expansion of the glass.

Question

1. A glass flask whose volume is exactly 1000cm^3 at 0 degrees Celsius is completely filled with mercury at this temperature. When the flask and mercury are heated to 100 degrees Celsius, 15.2cm^3 of mercury overflow. If the coefficient of volume expansion of mercury is 18 x 10^-5 per Celsius degree, compute the coefficient volume expansion of the glass.

thanks.

Answer 1

15.2 = 1000 * (alpham-alphag)* 100

alpham - alphag = 15.2*10^-5
alphag = 18*10^-5 - 15.2*10^05 = 2.8*10^-5

Answer 2

The increase in volume of the mercury MINUS the increase in the flask is the overflow. The flask volume expansion is

delta Vf = V *(alphag) * delta T

Voverflow = deltaVm - deltaVg

Use that relationship and the calculated expansion of the mercury volume, delta Vm, to solve for alphag, the coefficient of thermal expansion of the glass.

Answer 3

I can't the answer. I don't understand. the answer in the book is 2.8 x 10^-5 per degree Celsius.

Answer 4

wow thanks. it made my mind clear. thank you. :)

Answer 5

To compute the coefficient of volume expansion of the glass, we can use the principle of conservation of volume. According to this principle, the increase in volume of the mercury is equal to the volume of the overflow.

Let's calculate the increase in volume of the mercury:
ΔV_mercury = 15.2 cm^3

Next, let's calculate the change in temperature:
ΔT = 100°C - 0°C = 100°C

Now, we can use the formula for volume expansion:

ΔV_mercury = V_mercury * γ_mercury * ΔT

Where:
ΔV_mercury is the change in volume of the mercury
V_mercury is the initial volume of the mercury (1000 cm^3)
γ_mercury is the coefficient of volume expansion of mercury (18 x 10^-5 per °C)
ΔT is the change in temperature

Plugging in the known values:

15.2 cm^3 = 1000 cm^3 * (18 x 10^-5 per °C) * 100°C

Simplifying the equation:

15.2 cm^3 = 1.8 cm^3 * 10^-2 * 1000

Now, we can solve for 1.8 cm^3:

1.8 cm^3 = 15.2 cm^3 / (10^-2 * 1000)

1.8 cm^3 = 15.2 cm^3 / 10

1.8 cm^3 = 1.52 cm^3

Finally, the coefficient of volume expansion of the glass can be calculated as follows:

γ_glass = ΔV_glass / (V_glass * ΔT)

Since the volume of the flask does not change, ΔV_glass is zero. Therefore, the coefficient of volume expansion of the glass is also zero.

So, the coefficient of volume expansion of the glass is 0.

Answer 6

15.2 = 1000 * (alpham-alphag)* 100

The increase in volume of the mercury MINUS the increase in the flask is the overflow. The flask volume expansion is

thanks

I can't the answer. I don't understand. the answer in the book is 2.8 x 10^-5 per degree Celsius.

wow thanks. it made my mind clear. thank you. :)

To compute the coefficient of volume expansion of the glass, we can use the principle of conservation of volume. According to this principle, the increase in volume of the mercury is equal to the volume of the overflow.

3.14*10^-4