Find an nth-degree polynomial function with real coefficients satisfying the given conditions.
i and 3 i are zero;
An expression using x as the variable. Simplify your answer.
all irrational and complex zeros come in conjugal pairs,
so if i is a zero , so is -i
if 3i is a zero , so is -3i
so we have f(x) = a(x-i)(x+i)(x-3i)(x+3i)
f(x) = a(x^2 + 1)(x^2 + 9)
also f(-2) = 65
a(4+1)((4+9) = 65
65a = 65
a = 1