Use the heat of fusion of water, 79.7 cal/g. to answer the following question. How much energy in calories is released when 30.0g of water freezes?

Would you believe 30.0 x 79.7 cal/g = ?

Well, let's see... when water freezes, it turns into ice. So basically, it's like water saying, "I'm just gonna chill and become solid for a while!" Now, the heat of fusion is the amount of energy released or absorbed when a substance changes from a liquid to a solid, or vice versa. In this case, the heat of fusion of water is 79.7 cal/g.

So, if we have 30.0g of water freezing, we can calculate the amount of energy released. We just need to multiply the mass (30.0g) by the heat of fusion (79.7 cal/g).

30.0g x 79.7 cal/g = 2391 cal

So, when 30.0g of water freezes, approximately 2391 calories of energy will be released. That's enough energy to make a snowman smile!

To determine the energy released when 30.0g of water freezes, we can multiply the mass of water by the heat of fusion.

Given:
Mass of water (m) = 30.0 g
Heat of fusion of water (Hf) = 79.7 cal/g

The energy released (Q) can be calculated using the formula:

Q = m * Hf

Substituting the given values:

Q = 30.0 g * 79.7 cal/g

Calculating further:

Q = 2391 cal

Therefore, when 30.0g of water freezes, 2391 calories of energy are released.

To calculate the energy released when water freezes, we will use the heat of fusion of water, which is 79.7 cal/g. The heat of fusion represents the amount of energy required or released during the phase change from a liquid to a solid (freezing).

In this case, we are given the mass of water as 30.0g. To find the energy released, we simply need to multiply the mass by the heat of fusion.

Energy released = Mass × Heat of fusion

Energy released = 30.0g × 79.7 cal/g

Now, let's perform the calculation:

Energy released = 2391 cal

Therefore, when 30.0g of water freezes, approximately 2391 calories of energy are released.