A rocket expels gas at the rate of 0.5kg/s.If the force produced by the rocket is 100N,what is the velocity with which the gas is expelled.
Force = rate of change of momentum
Propelling force=100N
m (of propelling agent)=0.5 kg / s
velocity=v
100 N=0.5 kg/s *v
=>
v=100/0.5 m/s
=200 m/s
This answer is the best and I think it is correct
F=ma
F= m*v/t
F=(m/t)*v
100/0.5=v
200m/s=v
V=200m/s
Well, if the rocket expels gas at a rate of 0.5 kg/s, we can assume that the gas is suffering from an extreme case of flatulence. Now, as for the force produced by the rocket being 100N, I must say that's quite impressive. It seems like the rocket had one too many beans!
To find the velocity with which the gas is expelled, we can use Newton's second law of motion: F = m * a. In this case, the force (F) is 100N and the mass (m) is 0.5kg/s. We want to find the acceleration (a) of the gas.
Using some mathematical wizardry, we can rearrange the equation to solve for acceleration: a = F/m. Plugging in the values, we get a = 100N / 0.5kg/s = 200 m/s².
And voila! The velocity with which the gas is expelled is 200 m/s². Just be glad you're not standing behind the rocket when it breaks wind!
To find the velocity with which the gas is expelled, we can use the concept of Newton's second law: force equals mass times acceleration (F = ma). In this case, the force is 100N and the mass is 0.5kg/s.
First, let's rearrange the equation to solve for acceleration:
a = F/m
Now, we can substitute the given values:
a = 100N / 0.5kg/s
To simplify this, we need to convert kg/s to kg. We know that 1 s is equivalent to 1 s, so we can multiply the rate (0.5kg/s) by 1s/1s:
a = 100N / (0.5kg/s * 1s/1s)
The s units cancel out:
a = 100N / 0.5kg
Now we can calculate the acceleration:
a = 200m/s^2
Since acceleration is the rate of change of velocity, we can determine that the velocity with which the gas is expelled is 200m/s.