I am not being lazy, I've tried to get this done several times, but I am VERY bad when it comes to fractions.
Barbara, Donna, Cindy, and Nicole ran in a relay race.
Barbara: 3 3/10
Donna: 2 4/5
Cindy: 3 2/5
Nicole: 2 1/10
1. The four girls ran in a relay race as a team. If each girl ran one part of the race, what was the team's total time?
2. Find the difference between the fastest girl's time and the slowest girl's time.
3. To break the school's record. the girls' time had to be faster than 12 2/5 minutes. Did the girls break the record? If so, how much faster were they? If not, how much slower were they?
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This is the same as the first one but with different people and times.
James: 2/3
Gilbert: 11/12
Matthew: 5/6
Simon: 7/12
4. The four boys ran in a relay race as a team. If each boy ran one part of the race, what was the team's total time?
5. Find the difference between the fastest boy's time and the slowest boy's time.
3. To break the school's record. The boy's time had to be faster than 2 7/12 minutes. Did the boys break the record? If so, how fast were they? If not, how much slower were they?
To me the two questions are the same.
What difference doe their names make??
The second is easier than the first, since it does not contain mixed fractions.
So let's start with the first one:
Step1 : get rid of those non-workable mixed fractions.
3 3/10 = 33/10
etc
1. for the first part you are now going to add those 4 fractions, after you found the LCD, which would be 10
2. Subtract the smallest fraction from the largest fraction.
3. The record is 12 2/5 minutes or 62/5 minutes.
Take the difference between 62/5 and the sum you got in the first part, then draw you conclusion.
Repeat those steps for the second question.
Did someone find the answer to this problem?
this is my school work but when I get the answer I will post it :)
um you never told us phantom of the opera
What difference doe their names make??
Looks like I can't make up my mind if it should be:
What difference do their names make??
or
What difference does their names make??
i know im stuck on it too
yea same i will tell you guys the answer when i get my work done this is part of my homework you have to wait for 2 or 3 days
To solve these questions involving fractions, we need to perform some basic arithmetic operations. Let's break down each question and explain how to find the answers step by step.
Question 1: The four girls ran in a relay race as a team. If each girl ran one part of the race, what was the team's total time?
To find the team's total time, we need to add up the individual times of each girl.
Barbara's time: 3 3/10 minutes
Donna's time: 2 4/5 minutes
Cindy's time: 3 2/5 minutes
Nicole's time: 2 1/10 minutes
To add these fractions, we need to find a common denominator. In this case, the least common denominator is 10.
Convert each fraction to have a denominator of 10:
Barbara's time: 3 3/10 = 33/10
Donna's time: 2 4/5 = 24/5
Cindy's time: 3 2/5 = 32/5
Nicole's time: 2 1/10 = 21/10
Now, let's add up these fractions:
33/10 + 24/5 + 32/5 + 21/10
Combine the numerators without changing the denominator:
(33 + 48 + 64 + 21)/10
Add up the numerators: 166/10
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 2 in this case:
(166 ÷ 2) / (10 ÷ 2) = 83/5
Therefore, the team's total time is 83/5 minutes.
Question 2: Find the difference between the fastest girl's time and the slowest girl's time.
To find the difference between the fastest girl's time and the slowest girl's time, we need to subtract the slower time from the faster time.
Faster time: 3 3/10 minutes
Slower time: 2 4/5 minutes
Convert both fractions to have the same denominator:
Faster time: 3 3/10 = 33/10
Slower time: 2 4/5 = 24/5
Now, subtract the slower time from the faster time:
33/10 - 24/5
To perform subtraction on fractions, we need a common denominator. In this case, the least common denominator is 10.
Convert both fractions to have a denominator of 10:
Faster time: 33/10
Slower time: 48/10
Now, subtract:
33/10 - 48/10 = (33 - 48)/10 = -15/10
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 5 in this case:
(-15 ÷ 5) / (10 ÷ 5) = -3/2
Therefore, the difference between the fastest girl's time and the slowest girl's time is -3/2 minutes, which can be interpreted as 1 1/2 minutes slower for the slowest girl compared to the fastest girl.
Question 3: To break the school's record, the girls' time had to be faster than 12 2/5 minutes. Did the girls break the record? If so, how much faster were they? If not, how much slower were they?
To determine if the girls broke the record, we need to compare their combined time to the record time.
Girls' combined time: 83/5 minutes
Record time: 12 2/5 minutes = 62/5 minutes
Compare the girls' combined time to the record time:
83/5 > 62/5
The girls' combined time is greater than the record time, which means they broke the record.
To find out how much faster they were, we need to subtract the record time from their combined time.
83/5 - 62/5 = (83-62)/5 = 21/5
Therefore, the girls were 21/5 minutes or 4 1/5 minutes faster than the record.
Moving on to the next set of questions:
Question 4: The four boys ran in a relay race as a team. If each boy ran one part of the race, what was the team's total time?
Similarly, follow the same steps as mentioned in Question 1 to determine the total time for the boys' team.
James's time: 2/3 minutes
Gilbert's time: 11/12 minutes
Matthew's time: 5/6 minutes
Simon's time: 7/12 minutes
Convert the fractions to have a common denominator, which is 12 in this case:
James's time: 8/12
Gilbert's time: 11/12
Matthew's time: 10/12
Simon's time: 7/12
Add up these fractions:
8/12 + 11/12 + 10/12 + 7/12 = (8 + 11 + 10 + 7)/12 = 36/12
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 12 in this case:
(36 ÷ 12) / (12 ÷ 12) = 3/1
Therefore, the team's total time is 3/1 or simply 3 minutes.
Question 5: Find the difference between the fastest boy's time and the slowest boy's time.
Apply the steps mentioned in Question 2 to find the difference between the fastest boy's time and the slowest boy's time.
Faster time: 2/3 minutes
Slower time: 11/12 minutes
Convert the fractions to have a common denominator, which is 12 in this case:
Faster time: 8/12
Slower time: 11/12
Now, subtract:
8/12 - 11/12 = (8 - 11)/12 = -3/12
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 3 in this case:
(-3 ÷ 3) / (12 ÷ 3) = -1/4
Therefore, the difference between the fastest boy's time and the slowest boy's time is -1/4 minutes, which can be interpreted as 1/4 minutes slower for the slowest boy compared to the fastest boy.
Question 3 (Revisited): To break the school's record, the boys' time had to be faster than 2 7/12 minutes. Did the boys break the record? If so, how fast were they? If not, how much slower were they?
Follow the same approach as mentioned in Question 3 to compare the boys' combined time to the record time.
Boys' combined time: 3 minutes
Record time: 2 7/12 minutes = 31/12 minutes
Compare the boys' combined time to the record time:
3 min > 31/12 min
The boys' combined time is greater than the record time, which means they broke the record.
To determine how fast they were, we need to subtract the record time from their combined time.
3 min - 31/12 min = (36/12 min - 31/12 min) = 5/12 min
Therefore, the boys were 5/12 minutes faster than the record.
http://www.mathisfun.com/ <~~Bookmark this website.
Click on Numbers. Then click on Fractions Menu.
Study this section carefully, including the explanations and the how-to examples.
What you need for these problems are the explanations for adding and subtracting fractions.
"what was the team's total time" = add
"Find the difference" = subtract
"Did the girls [boys] break the record?" = adding or subtracting depending on their time compared to the record time.