A car run until the gas tank is 1/8 full.the tank is then filled to capacity by putting in 14 gallons.the capacity of the gas tank of the car is........?

x/8 + 14 = x

To solve this problem, we can set up an equation:

Let C be the capacity of the gas tank of the car.

The car runs until the gas tank is 1/8 full, which means it has used 7/8 of the gas. So, after driving, there is 1/8 of the tank remaining.

We know that filling the tank to capacity requires 14 gallons.

Using this information, we can set up the equation:

(1/8) * C = 14

To solve for C, we can multiply both sides of the equation by 8:

C = 14 * 8

Calculating the right side of the equation, we find:

C = 112

Therefore, the capacity of the gas tank of the car is 112 gallons.

To find the capacity of the gas tank of the car, we can use the information given.

Let's assume the capacity of the gas tank is "C" gallons.

According to the given information, the car runs until the gas tank is 1/8 full. This means that after driving until 1/8 of the tank is left, there is still 7/8 of the tank's capacity remaining.

So, the remaining capacity of the tank after driving until it's 1/8 full is (7/8) * C gallons.

Then, it's mentioned that 14 gallons are added to fill the tank to capacity. Therefore, we can set up the following equation:

(7/8) * C + 14 = C

To solve for C, we can simplify and solve the equation:

7/8C + 14 = C
Multiply through by 8 to eliminate the fraction:
7C + 112 = 8C
Subtract 7C from both sides:
112 = 8C - 7C
112 = C

Therefore, the capacity of the gas tank of the car is 112 gallons.