How many grams of ammonia are produced when 32g of nitrogen react with excess hydrogen?

N2 + 3H2 --> 2NH3

for every mol of N (not N2) you get one mol of NH

mols of N = 32 g /14 g/mol = 32/14
so we get (32/14) mols of NH3

NH3 = 14+3 = 17 g/mol

so
(32/14)(17) grams

To determine the grams of ammonia produced, we first need to calculate the number of moles of nitrogen and then use the balanced equation to find the number of moles of ammonia.

Step 1: Calculate the moles of nitrogen (N2):

Molar mass of N2 = 14 g/mol (1 nitrogen atom = 14 g/mol)

Moles of N2 = (mass of N2) / (molar mass of N2)
Moles of N2 = 32 g / 14 g/mol
Moles of N2 ≈ 2.29 mol

Step 2: Use the balanced equation to find the moles of ammonia (NH3):

According to the balanced equation:
1 mole of N2 reacts to produce 2 moles of NH3

Moles of NH3 = (moles of N2) × (moles of NH3/mole of N2)
Moles of NH3 = 2.29 mol × (2 mol NH3 / 1 mol N2)
Moles of NH3 ≈ 4.58 mol

Step 3: Convert moles of ammonia to grams:

Molar mass of NH3 = 17 g/mol (1 nitrogen atom + 3 hydrogen atoms = 17 g/mol)

Grams of NH3 = (moles of NH3) × (molar mass of NH3)
Grams of NH3 = 4.58 mol × 17 g/mol
Grams of NH3 ≈ 77.86 g

Therefore, approximately 77.86 grams of ammonia are produced when 32 grams of nitrogen react with excess hydrogen.

To determine how many grams of ammonia are produced when 32g of nitrogen reacts with excess hydrogen, we need to use the molar ratios of the balanced chemical equation.

The balanced chemical equation is:
N2 + 3H2 -> 2NH3

From the equation, we can see that 1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to produce 2 moles of ammonia (NH3).

To calculate the grams of ammonia produced, we need to follow these steps:

1. Find the molar mass of nitrogen (N2):
The molar mass of N2 is 28 grams per mole (2 * 14g/mol).

2. Calculate the number of moles of nitrogen (N2):
Divide the given mass of nitrogen (32g) by its molar mass (28g/mol):
32g / 28g/mol = 1.143 moles of N2.

3. Use the molar ratio from the balanced equation to determine the moles of ammonia produced:
From the balanced equation: 1 mole of N2 produces 2 moles of NH3.
So, 1.143 moles of N2 will produce:
1.143 moles * (2 moles of NH3/1 mole of N2) = 2.286 moles of NH3.

4. Calculate the grams of ammonia produced:
To do this, we need to find the molar mass of ammonia (NH3), which is 17 grams per mole (1 * 14g/mol + 3 * 1g/mol).

Multiply the number of moles of ammonia (2.286 moles) by its molar mass (17g/mol):
2.286 moles * 17g/mol = 38.862g.

So, when 32g of nitrogen reacts with excess hydrogen, approximately 38.862 grams of ammonia are produced.