Create an appealing scientific illustration. In the image, show a three-dimensional model of a blue crystal, which represents a copper sulphate pentahydrate (CuSO4.5H2O) molecule. Emphasize the sulfur atom in the center of this molecular model by color difference or incredible zoom. Add the oxidation process as an abstract concept, perhaps by using visual symbols like lightning bolts, radiating energy waves, or swirls of color. Also, there should be representations of atoms like copper, oxygen and hydrogen orbiting around the sulfur atom. Please ensure no text is included in the image.

The oxidation number of sulphur in CuSO4.5H2O is ......

Cu is +2

S is S
O is -2. 4*-2 = -8
All compounds add to zero.
Cu + S + 4*-2 = 0
2 + S +(-8) = 0
2 + S + -8 = 0
Solve for S.
S = 0 - 2 + 8 = ?

+6 because SO4 has no bracket

What about Hydrogen

CuSo4,5H2O

Cu=+2
O=-2*4 =-8
+2+x-8+2-2=0
X=+6

R7o3b6e2l5

The oxidizing agent is oxizided by the reduced agent

What about Hydrogen

6

The oxidation number of sulphur in CuSO4.5H2O is +6.

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