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a block of mass 0.1kg is attached to spring and placed on a horizontal frictionless table .the spring is stretched 20cm when a force of 5n is applied.calculate the spring constant

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3 answers

  1. F=kx
    K=5/0.2=50/2=25N/M
    T=2π✓m/K
    T=2×3.142✓0.1/25
    T=6.284×0.0632
    T=0.397Sec

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  2. force / distance

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  3. Yes

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