when pure sodium hydroxide is dissolved in water , heat is evolved in a laboratory experiment measure a molar heat of solution of sodium hydroxide the following procedure was followed. to a calorimeter containing 300g of water at 20.0 C and 10.65g of NaOH also at 20.0 C was added. the temperature change which was monitered by digital probe with neglible heat capacity stopped when it reached a temperature of 28.50C if the specific heat of the mixture is 4.184Jg-1c-1 and the small heat capacity of the calorimeter is ignored what is Delta H for the solution of one moleof NaOH? the molar mass of NaOH is 40.09.

Compute the heat generated, Q, using the temperature rise and the mass M and heat capacity C of H2O.
Q = M C (delta T)
delta t is the 8.50 C change in temperature.
Divide Q by the number of moles of NaOH to get the deltaH per mole.

heat of solution is
massH2O*specificheatwater*deltaTH2O =
300g*4.184*(28.50-20.0) = ??joules.

??joules is the heat for 10.65g NaOH.
Convert to ?? joules/40.09 mol.
This is the heat of solution/mol NaOH.
Post your work if you get stuck.

260

usthe following data of the results of a titration with potassium hydroxide (KOH),calculate the concentration of sulfuric (H2SO4.

Burette reading from the titration of 20.0 ml of sulfuric acid with potassium hydroxide
TRIAL INITIAL VOLUME(ML) FINALVOLUME(ML)
1 0.0 23.0
2 23.0 47.0
3 0.0 2305

First, let's calculate the heat generated, Q, using the formula Q = M C (delta T). Here, M is the mass of water, C is the specific heat capacity of the mixture, and delta T is the change in temperature.

Given:
Mass of water (M) = 300g
Specific heat capacity of the mixture (C) = 4.184 J/g°C
Change in temperature (delta T) = 28.50°C - 20.0°C = 8.50°C

Using the formula, Q = (300g)(4.184 J/g°C)(8.50°C), we can calculate the heat generated.

Q = 10,056 J

The heat generated, Q, is 10,056 Joules.

Next, we need to determine the heat of solution for 10.65g of NaOH.

Using the heat generated, Q, we can set up a ratio to find the heat of solution for 10.65g of NaOH.

(Q for 10.65g NaOH)/(10.65g NaOH) = (Q for 1 mole NaOH)/(1 mole NaOH)

Let's calculate the heat of solution for 10.65g of NaOH.

(Q for 10.65g NaOH)/(10.65g NaOH) = (10,056 J)/(10.65g)

Now, we need to convert the heat of solution for 10.65g of NaOH to Joules/mol NaOH.

To convert to Joules/mol NaOH, we need to divide the value obtained in the previous step by the molar mass of NaOH.

Let's calculate the heat of solution per mole of NaOH.

Heat of solution/mol NaOH = (10,056 J)/(10.65g) / 40.09 g/mol

Finally, let's calculate the value of heat of solution/mol NaOH.

Heat of solution/mol NaOH = (10,056 J)/(10.65g) / 40.09 g/mol = ??

You can now calculate the final value using a calculator.

To solve this problem, we need to follow these steps:

Step 1: Calculate the heat generated, Q, using the equation Q = MC(delta T), where M is the mass of water, C is the specific heat of water, and delta T is the change in temperature.

Given:
Mass of water, M = 300g
Specific heat of water, C = 4.184 J/g°C
Change in temperature, delta T = 28.50°C - 20.0°C = 8.50°C

Using Q = MC(delta T):
Q = 300g * 4.184 J/g°C * 8.50°C

Step 2: Calculate the heat generated for 10.65g of NaOH using the value obtained in step 1.

Given:
Mass of NaOH, m = 10.65g

The heat generated for 10.65g of NaOH is equal to the heat generated for the water. Therefore, we can say:
Q (heat for water) = Q (heat for NaOH)

Step 3: Calculate the heat of solution per mole of NaOH.

To do this, we need to convert the heat generated for 10.65g of NaOH to joules/mol NaOH.

To convert from grams to moles, we use the molar mass of NaOH.
Molar mass of NaOH = 40.09 g/mol

To find the heat of solution per mole of NaOH, we divide the heat generated (Q) by the number of moles of NaOH.

Heat of solution per mole of NaOH = (Q in joules) / (number of moles of NaOH)
= Q / (10.65g / 40.09g/mol)

Now, you can plug in the values and calculate the heat of solution per mole of NaOH.