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If a seed is planted, it has a 70% chance of growing into a healthy plant.

If 7 seeds are planted, what is the probability that exactly 1 doesn't grow?

Here What I did I thought its premutation but some reason I got that wrong, I multiple by (0.10) and (0.70) of the seeds I still got it wrong. Where did I got it wrong

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  1. No, this is an example of Binomial Distribution.

    You are planting 7 plants, and you want the prob that exactly 1 does not grow.

    Suppose it is the 3rd plant which did not grow.
    GGNGGGG, where G stands for grow, N for not grow.
    That specific probability is
    (.7)(.7)(.3)(.7)(.7)(.7)(.7)
    = (.7^6)(.3)

    but it could have been 7 different arrangements of G's and N
    e.g.
    GGGGGNG is another case

    So you the prob as
    7 (.7)^(.3)
    = appr .247

    or

    C(7,1) (.7)^6 (.3) = appr .247

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