The molar mass of sucrose, or table sugar, is 342 grams. Calculate how many grams of sucrose are required to make 3.0 liters of 0.50M sucrose solution.
513 g
0.50
Two definitions to know:
(1)
Molarity = #mols/liter of solution.
(2)
# mols = grams/molar mass.
From #1, you know molarity and liters, calculate mols. From #2, plug in mols and molar mass to calculate grams.
513 g
513 g of sucrose powder to make 0.5 M for 3.0 Liters
To calculate how many grams of sucrose are required to make the sucrose solution, we can use the formula:
mass = moles × molar mass
First, let's calculate the number of moles of sucrose required:
moles = Molarity × volume
Given:
Molarity (M) = 0.50 M
Volume (V) = 3.0 liters
moles = 0.50 M × 3.0 liters
moles = 1.5 moles
Now, we can calculate the mass of sucrose required using the molar mass given:
mass = moles × molar mass
mass = 1.5 moles × 342 grams/mole
mass ≈ 513 grams
So, approximately 513 grams of sucrose are required to make 3.0 liters of 0.50M sucrose solution.