how much energy is released during the reaction of 2.5l diboron hexahydride with 5.65l chlorine gas?
To determine the energy released during the reaction of 2.5 L of diboron hexahydride (B2H6) with 5.65 L of chlorine gas (Cl2), we need to use the concept of stoichiometry and the balanced chemical equation for the reaction.
First, we need to write the balanced chemical equation for the reaction of diboron hexahydride (B2H6) with chlorine gas (Cl2):
B2H6 + 6Cl2 -> 2BCl3 + 6HCl
From the balanced equation, we can see that for every 2 moles of diboron hexahydride, 6 moles of chlorine gas react to produce 2 moles of boron trichloride (BCl3) and 6 moles of hydrogen chloride (HCl).
Now, let's calculate the moles of each reactant:
For diboron hexahydride (B2H6):
2.5 L * (1 mole/22.4 L) = 0.11176 moles
For chlorine gas (Cl2):
5.65 L * (1 mole/22.4 L) = 0.25223 moles
We can see from the balanced equation that the mole ratio of diboron hexahydride to energy released is 2:6 or 1:3. This means that for every 2 moles of diboron hexahydride reacted, 3 moles of energy are released.
To calculate the energy released, we need to multiply the moles of diboron hexahydride by the ratio of energy released:
0.11176 moles * (3/2) = 0.16764 moles of energy released
Finally, we need to convert the moles of energy released to energy units. The energy released is typically in joules (J) or kilojoules (kJ).
To do this, we need to know the enthalpy change of the reaction (ΔH). If the enthalpy change is given in kilojoules per mole (kJ/mol), we can multiply the moles of energy released by the enthalpy change (per mole) to get the total energy released:
Energy released = 0.16764 moles * ΔH
If the value of ΔH is not provided, it is not possible to determine the exact amount of energy released in this reaction. The enthalpy change for the given reaction would need to be known or calculated using experimental or theoretical data.
Do you have an equation?
B2H6 + 6Cl2 ==> 2BCl3 + 6HCl
Convert 2.5 L B2H6 to mols
Do the same for 5.65 L Cl2.
These are gases. What's the pressure? the T?
Determine which is the limiting reagent.
See if this will help you.
https://socratic.org/questions/according-to-the-following-reaction-how-much-energy-is-evolved-during-the-reacti