A person walks on the building.He slips 1m for every 5m he climbs. If the building is 53m high and he takes 5 seconds to climb 1m. Find the total time taken by him to get on the top of the building.
5m=25seconds
5-1=4m(as he slips 1m for every5m)
Total height of building=53m
He will ned53/4=13sec(Remainder 1ignored)
25*3=325seconds
So, he needs 325sec to climb the building.
Answer upper bale ka galat h
To find the total time taken by the person to climb the building, we need to calculate the time taken to climb each individual meter and then sum them up.
Given:
- The person slips 1m for every 5m climbed.
- The building is 53m high.
- The person takes 5 seconds to climb 1m.
First, let's calculate the number of times the person slips when climbing the building. For every 5m climbed, the person slips 1m, so we can calculate the number of times the person slips as:
Number of slips = Height of the building / Distance of each slip
Number of slips = 53m / 5m
Number of slips = 10.6
Since the person cannot slip a fractional number of times, we can consider that the person slips 10 times while climbing the building.
Now let's calculate the time taken for each meter of the climb. The person takes 5 seconds to climb 1m, so the time taken for 1m is 5 seconds.
To find the total time taken by the person, we need to calculate:
Total time taken = Time taken for climbing each meter * Number of meters
Since the person slips 10 times when climbing the building, the total number of meters climbed is:
Total number of meters climbed = Height of the building + Number of slips
Total number of meters climbed = 53m + 10m
Total number of meters climbed = 63m
Now, we can calculate the total time taken by the person to climb the building:
Total time taken = Time taken for climbing each meter * Total number of meters climbed
Total time taken = 5 seconds/meter * 63 meters
Total time taken = 315 seconds
Therefore, the person takes a total of 315 seconds to get to the top of the building.
Yes
5m 25sec.
Since you don't say that each 5m portion is a separate attempt (like walking up stairs), I'll assume that his slippage is continuous as he climbs.
That is, it takes him 5*5=25 seconds to climb 5-1=4 meters.
So, his rate of ascent is 4/25 m/s
It will take him 53/(4/25) = 1325/4 = 331.25 seconds to make the climb.
If the climb has to be broken into discrete chunks of 5m each, then things change some.
(n-1)×25/4=325sec
Where n=53
&4m in25 sec