two forces are acting on an object. F1= 60 N is horizontal while F2= -80N is vertical, what is the magnitude of the net force acting on the object?

The answer is 100 N, can some one please explain it though?

the forces are vectors that add by Pythagoras

60^2 + 80^2 = 100^2

To find the magnitude of the net force acting on the object, you need to determine the vector sum of the two forces. Here's how you can explain it step by step:

1. Start by drawing a diagram to visualize the forces. Draw a horizontal line to represent the horizontal force F1 = 60 N, and a vertical line to represent the vertical force F2 = -80 N. Remember that the negative sign indicates that the force is acting in the opposite direction.

2. Now, use the Pythagorean theorem to calculate the magnitude of the net force. The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, horizontal force F1 is the adjacent side, and vertical force F2 is the opposite side of a right-angle triangle.

Using the Pythagorean theorem:
Net force (Fnet) = √(F1^2 + F2^2)
Fnet = √((60 N)^2 + (-80 N)^2)
Fnet = √(3600 N^2 + 6400 N^2)
Fnet = √(10000 N^2)
Fnet = 100 N

Therefore, the magnitude of the net force acting on the object is 100 N.