A) Write a balanced chemical equation for the reaction between sulfuric acid and potassium hydroxide.

I got H2SO4 + KOH ---> H2OH + KSO4
B) Write the ionic equation for the reaction.
H2 + S2O4-2 + K + OH- ---> H2 + OH + K2SO4-2
C) Write the net ionic equation
I'm not sure if B is right so I can't do this one

A is incorrect. Both the products and the balancing are incorrect. What is H2OH? What is KSO4. The products are H2O and K2SO4. I will leave it for you to balance. To balance, YOU MAY NOT CHANGE any of the subscripts; you may change ONLY the coefficients.

For B, you put the molecules in the form of ions.
2H^+ + SO4^-2 + 2K^+ + 2OH^- ==> 2H2O + 2K^+ + SO4

For C, look at the answer for B I have written above, cancel ions that are on both sides of the equation. What is left is the net ionic equation. (For example, the SO4^-2 is on the leeft AND on the right, so cancel it. Etc.)

C'mon. You're making it too hard.
Put a 2 in front of KOH and a 2 in front of the H2O and that's it. Check my work to make sure it's right.

I have tried and tried but I can NOT balance this equation I just cant figure this thing out. can someone please help me

H2SO4 + KOH ---> H2O + K2SO4

your right. I just kept looking at it wrong for some reason thanks.

H2SO4 + K=====>KSO4 + H2. Ionic equation:..... H2SO4 + K*===>K*(aq) +SO4(aq)+H2. Net eqn. H2SO4===>SO4^2- + H2........I'm confused because I've Cross 2(K*),but not satisfied with the net ionic equation.Please could someone help me recheck my answer?

SO4-2 2KOH2H2O

No problem! Balancing chemical equations can sometimes be tricky, but with practice, it becomes easier. Remember to always check that the number of atoms of each element is the same on both sides of the equation. If you have any more questions, feel free to ask!

No problem! Balancing chemical equations can be tricky sometimes. It's important to keep in mind that we must have the same number of atoms on both sides of the equation to ensure that mass is conserved.

In this case, the balanced chemical equation is:

H2SO4 + 2KOH → 2H2O + K2SO4

To balance the equation, we need two hydroxide ions (OH-) on the left side to react with the sulfuric acid (H2SO4). This gives us two water molecules as products. Additionally, we need two potassium ions (K+) on the left side to balance with the sulfate (SO4^-2) ion on the right side.

Always remember that balancing equations takes practice, and it's normal to make mistakes along the way. It's great that you were able to identify the error and correct it. Keep up the good work!