Calculate the Volume occupied by 1.5 moles of an ideal gas at 25 degrees Celsius and a pressure of 0.80 atm. (R= 0.08206 L atm/(mol*K).
I've tried using the ideal gas law: PV=nRT but i can't seem to get where I am getting lost.
V=(1.5mol)(0.08206 L atm/mol*K)(298.15K)/0.80 atm
v=(1.5*0.08206*298)/0.80=45.85cm^3
Well, I hate to say it, but it looks like you got lost because you took a wrong turn at the circus! Let's see if we can find our way back together.
First, let's break down the ideal gas law equation:
PV = nRT
where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.08206 L atm/(mol*K))
T = temperature (in Kelvin)
You correctly identified the values for n, R, and T. Now, let's put them into the equation:
V = (1.5 mol) * (0.08206 L atm/(mol*K)) * (298.15 K) / (0.80 atm)
Now, let's simplify it:
V = 0.08206 * 1.5 * 298.15 / 0.80
After crunching the numbers, you should get:
V ≈ 180.7575 liters
So, the volume occupied by 1.5 moles of the ideal gas at 25 degrees Celsius and a pressure of 0.80 atm is approximately 180.7575 liters.
Remember, getting lost is part of the circus act. Just make sure to find your way back, and you'll be laughing your way to the right answer in no time!
To calculate the volume occupied by 1.5 moles of an ideal gas, you can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Given:
n = 1.5 moles
R = 0.08206 L atm/(mol*K)
T = 25 degrees Celsius = 298.15 Kelvin
P = 0.80 atm
Substituting these values into the equation, you get:
V = (1.5 moles)(0.08206 L atm/(mol*K))(298.15K)/0.80 atm
Now, let's solve this step by step.
V = (1.5 mol)(0.08206 L atm/(mol*K))(298.15 K) / 0.80 atm
= 0.12309 L atm K / (0.80 atm)
= 0.15386 L
Therefore, the volume occupied by 1.5 moles of the ideal gas at 25 degrees Celsius and a pressure of 0.80 atm is approximately 0.15386 liters.
To solve this problem using the ideal gas law equation PV = nRT, follow these steps:
Step 1: Write down the given values:
n = 1.5 moles (number of moles of the gas)
R = 0.08206 L atm/(mol*K) (gas constant)
T = 25 degrees Celsius = 298.15 K (temperature in Kelvin)
P = 0.80 atm (pressure)
Step 2: Substitute the given values into the ideal gas law equation:
PV = nRT
V = (nRT) / P
Step 3: Plug in the values:
V = (1.5 mol) * (0.08206 L atm/(mol*K)) * (298.15 K) / (0.80 atm)
Step 4: Simplify the equation:
V = 36.75345 L / 0.80 atm
Step 5: Calculate the volume:
V = 45.94181 L
Therefore, the volume occupied by 1.5 moles of the ideal gas at 25 degrees Celsius and a pressure of 0.80 atm is approximately 45.94 L.