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Calculate the Volume occupied by 1.5 moles of an ideal gas at 25 degrees Celsius and a pressure of 0.80 atm. (R= 0.08206 L atm/(mol*K).

I've tried using the ideal gas law: PV=nRT but i can't seem to get where I am getting lost.

V=(1.5mol)(0.08206 L atm/mol*K)(298.15K)/0.80 atm

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1 answer
  1. v=(1.5*0.08206*298)/0.80=45.85cm^3

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