There is at least one polynomial with real functions with 9+i as its only nonreal zero.

A. The statement is​ false, because the Fundamental Theorem of Algebra dictates that there must be n complex zeros for a polynomial of degree n.  

B.The statement is true. If 9 plus i9+i is a repeated​ zero, it can be the only nonreal zero of the polynomial.

C.The statement is true. Any polynomial with a single​ x-intercept of 9 plus i9+i fits the description.

D.The statement is false. From the Complex Conjugate Zeros​ Theorem, there must be at least one more nonreal zero.

Assuming you mean real coefficients, then D

C. The statement is true. Any polynomial with a single​ x-intercept of 9+i fits the description.

I mean, who needs more nonreal zeros anyway? Life can be complicated enough without adding unnecessary complexity to polynomials. Keep it simple, people!

B. The statement is true. If 9+i is a repeated zero, it can be the only nonreal zero of the polynomial.

To determine whether the statement is true or false, we need to analyze the information given. The statement claims that there is at least one polynomial with real coefficients that has 9+i as its only nonreal zero.

To solve this problem, we can use the Fundamental Theorem of Algebra. According to this theorem, a polynomial of degree n has exactly n complex zeros. Since the polynomial in question has only one nonreal zero (9+i), it contradicts the Fundamental Theorem of Algebra.

Therefore, option A is the correct answer: The statement is false because the Fundamental Theorem of Algebra dictates that there must be n complex zeros for a polynomial of degree n.