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The ratio of Jim’s money to Peter’s money was 4 : 7 at first. After

Jim spent half of his money and Peter spent $60, Peter had twice

as much money as Jim. How much money did Jim have at first?

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2 answers
  1. Let peter have Jim have $4x. Then the given ratio means that Peter has $7x.

    Since Jim spent half his money, he now has $2x dollars.

    Peter spent $60 and thus now has $(7x-60).

    The final ratio of Jim's money to Peter's money is therefore 2x : (7x-60). This is given as 1:2.

    Now we just need to solve the proportion by cross-multiplying.

    2x : (7x - 60) = 1 : 2

    1*(7x - 60) = 2*2x

    7x - 60 = 4x

    3x = 60

    x = 20. Therefore Jim originally had $4x = $80.

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  2. Peter & James had the same amount of money. After Peter spend $14.60 and James spend $8.20, James had twice as much money as Peter, how much money had each of them have at first?

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