On vacation, your 1400-kg car pulls a 520-kg trailer away from a stoplight with an acceleration of 2.00 m/s2 .
A: What is the net force exerted by the car on the trailer?
Assume that the positive x axis is directed toward the direction of motion.
F = N
What force does the trailer exert on the car?
Assume that the positive x axis is directed toward the direction of motion.
F = N
PART C
What is the net force acting on the car?
Assume that the positive x axis is directed toward the direction of motion.
I FOUND THIS ANSWER F= 200 N
To find the net force exerted by the car on the trailer, you can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a).
Given:
Mass of the car (m1) = 1400 kg
Mass of the trailer (m2) = 520 kg
Acceleration (a) = 2.00 m/s^2
Net force exerted by the car on the trailer:
F = m1 * a + m2 * a
F = (1400 kg)(2.00 m/s^2) + (520 kg)(2.00 m/s^2)
F = 2800 N + 1040 N
F = 3840 N
Therefore, the net force exerted by the car on the trailer is 3840 N.
To find the force that the trailer exerts on the car, we can use Newton's third law of motion, which states that the force exerted by object A on object B is equal in magnitude but opposite in direction to the force exerted by object B on object A.
Since the net force exerted by the car on the trailer is 3840 N, the force exerted by the trailer on the car will also be 3840 N, but in the opposite direction. Thus, the force the trailer exerts on the car is -3840 N.
Finally, to find the net force acting on the car, we need to consider both the force exerted by the car on the trailer and the force exerted by the trailer on the car. The net force is the vector sum of these two forces.
Net force acting on the car:
F = F1 + F2
F = 3840 N - 3840 N
F = 0 N
Therefore, the net force acting on the car is 0 N.
To find the net force exerted by the car on the trailer, we can use Newton's second law of motion, which states that force (F) equals mass (m) times acceleration (a). In this case, the mass of the car is 1400 kg and the acceleration is 2.00 m/s^2. Therefore,
F = m * a
F = 1400 kg * 2.00 m/s^2
F = 2800 N
This means that the net force exerted by the car on the trailer is 2800 N.
To find the force exerted by the trailer on the car, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. Therefore, the force exerted by the trailer on the car is equal in magnitude but opposite in direction to the force exerted by the car on the trailer.
So, the force exerted by the trailer on the car is also 2800 N, but it is directed in the opposite direction.
To find the net force acting on the car, we need to consider both the force exerted by the car on the trailer and the force exerted by the trailer on the car. These two forces are equal in magnitude but opposite in direction, so they cancel each other out. Therefore, the net force acting on the car is zero.
However, your answer of 200 N for the net force acting on the car seems incorrect. Please double-check your calculations or provide more information if needed.
m a = 520*2 = 1040 N
third law ---> -1040 N
net force on car = car mass * car a
= 1400 * 2 = 2800 N
the tires exert 1040 N more on the road to accelerate the trailer, but that is not what you asked :)