Create balanced equation, given the two compounds in aqueous solution may react with one another. State whether or not a chemical reaction occurs. Make sure to include the state of each reactant and product. If a precipitation reaction occurs, provide the ionic and net ionic equations.
1) A sodium chloride solution mixes with a potassium hydroxide to yield:
2) Ammonium sulfate reacts with barium hydroxide to yield:
3) Barium hydroxide reacts with zinc(II) iodide reacts to yield:
There is a chapter of work here. What do you not understand about each? How much do you know how to do?
1) To create a balanced equation, we need to determine the chemical formulas of the reactants and products. In this case, we have sodium chloride (NaCl) and potassium hydroxide (KOH).
The balanced equation for the reaction can be written as:
2NaCl(aq) + KOH(aq) → 2NaOH(aq) + KCl(aq)
In this reaction, sodium chloride and potassium hydroxide react to form sodium hydroxide and potassium chloride. All the compounds are in aqueous state, indicated by (aq). To determine if a chemical reaction occurs, we need to check if any precipitates are formed.
2) For the second equation, we have ammonium sulfate ( (NH4)2SO4) and barium hydroxide (Ba(OH)2).
The balanced equation for the reaction can be written as:
(NH4)2SO4(aq) + Ba(OH)2(aq) → 2NH4OH(aq) + BaSO4(s)
In this reaction, ammonium sulfate and barium hydroxide react to form ammonium hydroxide and barium sulfate. The (s) indicates that barium sulfate is a solid precipitate. To find the net ionic equation, we need to remove the spectator ions. The net ionic equation is:
(NH4)2SO4(aq) + Ba(OH)2(aq) → 2NH4OH(aq) + BaSO4(s)
3) Lastly, we have barium hydroxide (Ba(OH)2) and zinc(II) iodide (ZnI2).
The balanced equation for the reaction can be written as:
Ba(OH)2(aq) + ZnI2(aq) → Zn(OH)2(s) + BaI2(aq)
In this reaction, barium hydroxide and zinc(II) iodide react to form zinc hydroxide and barium iodide. The (s) indicates that zinc hydroxide is a solid precipitate. To find the net ionic equation, we need to remove the spectator ions. The net ionic equation is:
Ba(OH)2(aq) + ZnI2(aq) → Zn(OH)2(s) + BaI2(aq)
In both reactions, a chemical reaction occurs and precipitates are formed.