. A student mixed the following reactants, using the general procedure for the experiment:

10.0 mL of 0.10 M KI, 10.0 mL of 0.0010 M Na2S2O3, 20.0 mL of 0.040 M K2S2O8, and 10.0 mL of 0.10M HCl. It took about 75 seconds for the mixture to turn blue.

a. By using the dilution equation (M1V1=M2V2), calculate the concentrations of each
reactant in the mixture after all of the solutions have been combined:
[I-] = ________ [S2O32-] = ________ [H+] = ________

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To calculate the concentrations of each reactant in the mixture using the dilution equation (M1V1=M2V2), we need to determine the moles of each reactant.

First, let's start with [I-]:
Molarity of KI solution (M1) = 0.10 M
Volume of KI solution (V1) = 10.0 mL = 0.010 L

Using the dilution equation:
Molarity of I- after dilution (M2) = M1 * V1 / V2

Since the volume of the final mixture is the sum of all the volumes of the reactants:
Volume of the final mixture (V2) = 10.0 mL + 10.0 mL + 20.0 mL + 10.0 mL = 50.0 mL = 0.050 L

Substituting the values into the equation:
M2 = (0.10 M) * (0.010 L) / (0.050 L)

Simplifying the equation:
M2 = 0.02 M

Therefore, the concentration of [I-] in the mixture is 0.02 M.

Next, let's calculate [S2O32-]:
Molarity of Na2S2O3 solution (M1) = 0.0010 M
Volume of Na2S2O3 solution (V1) = 10.0 mL = 0.010 L

Using the dilution equation:
Molarity of S2O32- after dilution (M2) = M1 * V1 / V2

Substituting the values into the equation:
M2 = (0.0010 M) * (0.010 L) / (0.050 L)

Simplifying the equation:
M2 = 0.0002 M

Therefore, the concentration of [S2O32-] in the mixture is 0.0002 M.

Lastly, let's find the concentration of [H+]:
Molarity of HCl solution (M1) = 0.10 M
Volume of HCl solution (V1) = 10.0 mL = 0.010 L

Using the dilution equation:
Molarity of H+ after dilution (M2) = M1 * V1 / V2

Substituting the values into the equation:
M2 = (0.10 M) * (0.010 L) / (0.050 L)

Simplifying the equation:
M2 = 0.02 M

Therefore, the concentration of [H+] in the mixture is 0.02 M.

Hence, the concentrations in the mixture are:
[I-] = 0.02 M
[S2O32-] = 0.0002 M
[H+] = 0.02 M