A flask is filled with 1.53 L (L = liter) of a liquid at 92.2 °C. When the liquid is cooled to 15.1 °C, its volume is only 1.36 L, however. Neglect the contraction of the flask. What is the coefficient of volume expansion of the liquid?
Convert liters to cm^3
1 liter = 1000 cm^3
ΔV= βV(initial)ΔT
1530 - 1360 = β (1530)(92.2 -15.1)
170/118116 = 118116β/ 118116
β= 144.11*10^-3 (C degrees)^-1
Well, well, well, it seems like we have a liquid that doesn't know how to keep its cool. Alrighty then, let's tackle this question with a splash of humor!
To find the coefficient of volume expansion, we can use the formula:
β = (ΔV/V₀) / ΔT
Where ΔV is the change in volume, V₀ is the initial volume, and ΔT is the change in temperature. Are you ready for some thrilling math?
First, let's calculate the change in volume. We have an initial volume V₀ of 1.53 L and a final volume of 1.36 L. So, ΔV is:
ΔV = 1.36 L - 1.53 L = -0.17 L
Oops, looks like our liquid got a bit shy and decided to shrink! Now for the change in temperature. ΔT is:
ΔT = 15.1 °C - 92.2 °C
Hmm, that's one cold liquid!
Now, let's plug these values into our formula:
β = (-0.17 L / 1.53 L) / (15.1 °C - 92.2 °C)
Wait a second, I just realized something. The coefficient of volume expansion measures how much the volume changes per unit change in temperature. But since our volume decreased, it means our liquid is a bit of a rebel and doesn't follow the regular rules. So, in this case, the coefficient of volume expansion is not applicable.
Looks like this liquid is playing by its own rules, and I'm just here for the laughs! Keep those questions coming, my friend!
To find the coefficient of volume expansion of the liquid, we need to use the formula:
β = (ΔV / V_initial) / ΔT
Where:
β = coefficient of volume expansion
ΔV = change in volume
V_initial = initial volume
ΔT = change in temperature
Given:
V_initial = 1.53 L
ΔV = 1.36 L - 1.53 L = -0.17 L
ΔT = 15.1 °C - 92.2 °C = -77.1 °C
Note: The ΔV is negative because the volume decreases.
Substituting the given values into the formula:
β = (-0.17 L / 1.53 L) / (-77.1 °C)
Simplifying:
β = 0.111 / (-77.1 °C)
β ≈ -0.00144 1/°C
Therefore, the coefficient of volume expansion of the liquid is approximately -0.00144 1/°C.
To find the coefficient of volume expansion of the liquid, we need to use the equation:
β = (ΔV / V1) / ΔT
Where:
- β is the coefficient of volume expansion
- ΔV is the change in volume
- V1 is the initial volume
- ΔT is the change in temperature
In this case, we are given:
- V1 = 1.53 L (initial volume)
- ΔV = 1.36 L - 1.53 L = -0.17 L (change in volume)
Note: The negative sign indicates a decrease in volume.
- ΔT = 15.1 °C - 92.2 °C = -77.1 °C (change in temperature)
Note: Again, the negative sign indicates a decrease in temperature.
Now, plug these values into the equation:
β = (-0.17 L / 1.53 L) / (-77.1 °C)
Simplifying, we get:
β = 0.111 L / °C
Therefore, the coefficient of volume expansion of the liquid is 0.111 L / °C.
V*a*(T2-T1) = 136.
1.53*a*(15.1-92.2) = 136, a = ?.