A vector has the components Ax=−37m and Ay=44m.

Part A
What is the magnitude of this vector?
Express your answer to two significant figures and include appropriate units. the answer for part A is help me with b pls
57 m

Part B
What angle does this vector make with the positive x axis?

sqrt (37^2+44^2) = 57.49 = 57 meters

tan angle = 44/-37
angle = -50

x is - and y is +
so second quadrant
180 - 50 = 130

65

Well, looks like you're lost and need some direction—just like this vector! Don't worry, I'll help you find your way, or rather, find the angle.

To determine the angle that this vector makes with the positive x-axis, we can use the tangent function. The tangent of an angle is equal to the ratio of the opposite side to the adjacent side. In this case, the opposite side is Ay and the adjacent side is Ax.

So, we'll just plug in the values, perform some calculations, and ta-dah! We'll have your angle. No GPS needed, just a little trigonometry!

Now, the tangent of the angle is given by:

tan(angle) = Ay / Ax

Plugging in the values, we get:

tan(angle) = 44m / (-37m)

Calculating this, we find:

angle = -51.8 degrees

So, the angle this vector makes with the positive x-axis is -51.8 degrees. And hey, don't worry about the negative sign, it's just the vector clowning around!

To determine the magnitude of a vector, you can use the Pythagorean theorem. The magnitude of a vector is the square root of the sum of the squares of its components.

In this case, the vector has components Ax = -37 m and Ay = 44 m. To find the magnitude, follow these steps:

1. Square each component: (-37 m)^2 = 1369 m^2, and (44 m)^2 = 1936 m^2.
2. Add the squares: 1369 m^2 + 1936 m^2 = 3305 m^2.
3. Take the square root: √3305 m^2 ≈ 57 m.

So, the magnitude of the vector is 57 m.

Now, let's move on to Part B, determining the angle that this vector makes with the positive x-axis.

To find the angle, you can use the inverse tangent function (tan^(-1)). The angle can be calculated as the ratio of the vertical component (Ay) to the horizontal component (Ax). The formula is:

angle = tan^(-1) (Ay / Ax)

Substituting the values, we have:

angle = tan^(-1) (44 m / -37 m)

Using a calculator or a math tool with trigonometric functions, we find that the angle is approximately -50.79 degrees.

However, since the vector has a negative Ax value, we need to adjust the angle. Adding 180 degrees to the calculated angle will give us the angle the vector makes with the positive x-axis:

angle = -50.79 degrees + 180 degrees ≈ 129.21 degrees.

Therefore, the angle between this vector and the positive x-axis is approximately 129.21 degrees.