A fighter accelerates from rest at 120,000 m/s^2 for a time of 4 seconds. How far did the jet fighter travel?
a = 120000 m/s^2
v = 120000t + c
when t=0, v = 0 , so c = 0
s = 60000t^2 + k , where s is the distance, k a constant
when t=0, the plane hasn't gone anywhere
so 0 = 0 + k, k = 0
s = 60000(t^2)
when t = 4, s = 60000(4) = ...
To find the distance traveled by the jet fighter, we can use the formula:
distance = initial velocity * time + 0.5 * acceleration * time^2
Given:
Initial velocity (u) = 0 m/s (as it starts from rest)
Acceleration (a) = 120,000 m/s^2
Time (t) = 4 seconds
Plugging in the values into the formula, we get:
distance = 0 * 4 + 0.5 * 120,000 * (4^2)
Simplifying:
distance = 0 + 0.5 * 120,000 * 16
= 0 + 0.5 * 1,920,000
= 960,000 meters
Therefore, the jet fighter traveled a distance of 960,000 meters.