4x-3y=11,and 2x+5y=25, substitution method

well, 2x = 25-5y

So, use that:

4x-3y = 11
2(2x)-3y = 11
2(25-5y)-3y = 11
50-10y-3y = 11
-13y = -39
y = 3

Now use that to find x.

Collect

from the second:

4x + 10y = 50
4x = 50-10y

into the first:
50-10y - 3y = 11
-13y = -39
y = 3

then 4x = 50 - 30
x = 5

IT IS NOT CORRECT

find x

2x+3y=11

4y-2x=10

From the second equation:

4y - 2x = 10

Rearrange it as:

-2x = -4y + 10

x = 2y - 5

Substitute this value in the first equation:

2(2y - 5) + 3y = 11

4y - 10 + 3y = 11

7y = 21

y = 3

Now substitute y = 3 in the equation x = 2y - 5:

x = 2(3) - 5

x = 1

Therefore, the solutions are x = 1 and y = 3.

To solve the system of equations using the substitution method, follow these steps:

1. Choose one equation and solve it for one variable in terms of the other variable. Let's choose the first equation, 4x - 3y = 11, and solve it for x.
4x - 3y = 11 (equation 1)
4x = 3y + 11
Divide both sides by 4: x = (3y + 11)/4

2. Substitute the expression you found for x into the other equation. Let's substitute x in the second equation, 2x + 5y = 25, with the expression (3y + 11)/4.
2((3y + 11)/4) + 5y = 25 (equation 2)

3. Simplify the equation and solve for y.
(3y + 11)/2 + 5y = 25
Multiply both sides by 2 to get rid of the fraction: 3y + 11 + 10y = 50
Combine like terms: 13y + 11 = 50
Subtract 11 from both sides: 13y = 50 - 11 = 39
Divide both sides by 13: y = 39/13 = 3

4. Substitute the value of y back into one of the original equations to find x. Let's use the first equation:
4x - 3(3) = 11
4x - 9 = 11
Add 9 to both sides: 4x = 11 + 9 = 20
Divide both sides by 4: x = 20/4 = 5

5. The solution to the system of equations is x = 5 and y = 3.